p
is a prime, a
be any integer,
We have
Example
It is a special case for Euler phi
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Nov 05, 20231 min read
p
is a prime, a
be any integer, a≡0(modp)
We have ap−1≡1(modp)
32018(mod17)=3126∗16+2=32=9
It is a special case for Euler phi